BASED ON STRING - Input: a1b2c3 Output: abbccc (ZOHO)

  

Consider the following I/O samples.

SAMPLE INPUT: i3j2k4

SAMPLE OUTPUT: iiijjkkkk

The algorithm used here is :

1. Input the string
2. Loop through the entire string to find the numbers.
3. After finding the number, repeat the previous character the same number of times.
4. Repeat steps 2 and 3 for the entire string.
5. Print the output.

C PROGRAM:  

#include<stdio.h>

#include<string.h>

int main()

{

   char str[100];

   int len=0,i,j,n;

   printf("Enter the string:");

   scanf("%s",&str);

   len=strlen(str);   

   for(i=0;i<len;i++)

   {

        if(str[i]>'0' && str[i]<'9')

        {

            n=str[i]-'0';

            for(j=0;j<n;j++)

                printf("%c",str[i-1]);

        }

   }

   return 0;

   }

OUTPUT:

The given source code in C program is short and simple to understand. The source code is well tested in DEV-C++ and is completely error free. 

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