C PROGRAM FOR 3 4 33 34 43 44

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 Consider the following I/O samples.


SAMPLE INPUT: 5

SAMPLE OUTPUT: 43


3 4 33 34 43 44 333 334 343 344 433 434 443 444 3333 3334 .........

for 1 - 3 ; 2 - 4 ; 7 - 333....


C PROGRAM:

#include<stdio.h>

int main()

{

   int n,b=1,ans=0;

    scanf("%d",&n);

    printf("\n");

    while(n)

    {

        if(n%2==1)

            ans=ans+3*b;

        else

            ans=ans+4*b;

        n=(n-1)/2;

        b=b*10;

    }

    printf("%d",ans);

    return 0;

}


OUTPUT:





The given source code in C program "for 3 4 33 34" is short and simple to understand. The source code is well tested in DEV-C++ and is completely error free. 

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